-36x^2+124x-104=0

Solution for -36x^2+124x-104=0 equation:

-36x^2+124x-104=0

a = -36; b = 124; c = -104;
Δ = b2-4ac
Δ = 1242-4·(-36)·(-104)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(124)-20}{2*-36}=\frac{-144}{-72}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(124)+20}{2*-36}=\frac{-104}{-72}
=1+4/9
$